Base | Representation |
---|---|
bin | 10111000000101011101101… |
… | …010100111010110010100111 |
3 | 111021022211001110110200011222 |
4 | 113000223231110322302213 |
5 | 101231043144241042411 |
6 | 555123320230050555 |
7 | 30213413634051605 |
oct | 2700535524726247 |
9 | 437284043420158 |
10 | 101202001112231 |
11 | 2a27858932a528 |
12 | b4257614a9a5b |
13 | 44614001a7316 |
14 | 1adc2bb004875 |
15 | ba7769edc4db |
hex | 5c0aed53aca7 |
101202001112231 has 2 divisors, whose sum is σ = 101202001112232. Its totient is φ = 101202001112230.
The previous prime is 101202001112197. The next prime is 101202001112237. The reversal of 101202001112231 is 132211100202101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101202001112231 - 210 = 101202001111207 is a prime.
It is a super-3 number, since 3×1012020011122313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101202001112237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50601000556115 + 50601000556116.
It is an arithmetic number, because the mean of its divisors is an integer number (50601000556116).
Almost surely, 2101202001112231 is an apocalyptic number.
101202001112231 is a deficient number, since it is larger than the sum of its proper divisors (1).
101202001112231 is an equidigital number, since it uses as much as digits as its factorization.
101202001112231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 101202001112231 its reverse (132211100202101), we get a palindrome (233413101314332).
The spelling of 101202001112231 in words is "one hundred one trillion, two hundred two billion, one million, one hundred twelve thousand, two hundred thirty-one".
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