Base | Representation |
---|---|
bin | 10111000000101011110011… |
… | …111011111011011111100111 |
3 | 111021022211100012010110101022 |
4 | 113000223303323323133213 |
5 | 101231043411133031043 |
6 | 555123335230521355 |
7 | 30213416451440504 |
oct | 2700536373733747 |
9 | 437284305113338 |
10 | 101202112002023 |
11 | 2a27863598968a |
12 | b42579266625b |
13 | 446141a161696 |
14 | 1adc2cba2c4ab |
15 | ba7774ae3868 |
hex | 5c0af3efb7e7 |
101202112002023 has 2 divisors, whose sum is σ = 101202112002024. Its totient is φ = 101202112002022.
The previous prime is 101202112001959. The next prime is 101202112002029. The reversal of 101202112002023 is 320200211202101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101202112002023 - 26 = 101202112001959 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101202112001992 and 101202112002010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101202112002029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50601056001011 + 50601056001012.
It is an arithmetic number, because the mean of its divisors is an integer number (50601056001012).
Almost surely, 2101202112002023 is an apocalyptic number.
101202112002023 is a deficient number, since it is larger than the sum of its proper divisors (1).
101202112002023 is an equidigital number, since it uses as much as digits as its factorization.
101202112002023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 101202112002023 its reverse (320200211202101), we get a palindrome (421402323204124).
The spelling of 101202112002023 in words is "one hundred one trillion, two hundred two billion, one hundred twelve million, two thousand, twenty-three".
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