Base | Representation |
---|---|
bin | 11101011101000010011… |
… | …01111111001110111011 |
3 | 10120202012120011001110022 |
4 | 32232201031333032323 |
5 | 113040110130110321 |
6 | 2052525550041055 |
7 | 133054565012534 |
oct | 16564115771673 |
9 | 3522176131408 |
10 | 1012022113211 |
11 | 36021811054a |
12 | 1441781a918b |
13 | 74582ba35b5 |
14 | 36da6d7d68b |
15 | 1b4d1e03dab |
hex | eba137f3bb |
1012022113211 has 2 divisors, whose sum is σ = 1012022113212. Its totient is φ = 1012022113210.
The previous prime is 1012022113181. The next prime is 1012022113213. The reversal of 1012022113211 is 1123112202101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1012022113211 - 210 = 1012022112187 is a prime.
Together with 1012022113213, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1012022113211.
It is not a weakly prime, because it can be changed into another prime (1012022113213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506011056605 + 506011056606.
It is an arithmetic number, because the mean of its divisors is an integer number (506011056606).
Almost surely, 21012022113211 is an apocalyptic number.
1012022113211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012022113211 is an equidigital number, since it uses as much as digits as its factorization.
1012022113211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1012022113211 its reverse (1123112202101), we get a palindrome (2135134315312).
The spelling of 1012022113211 in words is "one trillion, twelve billion, twenty-two million, one hundred thirteen thousand, two hundred eleven".
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