10120222071131 has 2 divisors, whose sum is σ = 10120222071132. Its totient is φ = 10120222071130.

The previous prime is 10120222071077. The next prime is 10120222071133. The reversal of 10120222071131 is 13117022202101.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10120222071131 - 2¹⁰ = 10120222070107 is a prime.

It is a super-2 number, since 2×10120222071131² (a number of 27 digits) contains 22 as substring.

Together with 10120222071133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10120222071097 and 10120222071106.

It is not a weakly prime, because it can be changed into another prime (10120222071133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060111035565 + 5060111035566.

It is an arithmetic number, because the mean of its divisors is an integer number (5060111035566).

Almost surely, 2^{10120222071131} is an apocalyptic number.

10120222071131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10120222071131 is an equidigital number, since it uses as much as digits as its factorization.

10120222071131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336, while the sum is 23.

Adding to 10120222071131 its reverse (13117022202101), we get a palindrome (23237244273232).

The spelling of 10120222071131 in words is "ten trillion, one hundred twenty billion, two hundred twenty-two million, seventy-one thousand, one hundred thirty-one".