Base | Representation |
---|---|
bin | 11101011101000100110… |
… | …11011011010100010011 |
3 | 10120202020222100101222121 |
4 | 32232202123123110103 |
5 | 113040130324211311 |
6 | 2052531553115111 |
7 | 133055232401545 |
oct | 16564233332423 |
9 | 3522228311877 |
10 | 1012042413331 |
11 | 360228616304 |
12 | 144182b58a97 |
13 | 745871604c1 |
14 | 36da9945695 |
15 | 1b4d3ab3b71 |
hex | eba26db513 |
1012042413331 has 2 divisors, whose sum is σ = 1012042413332. Its totient is φ = 1012042413330.
The previous prime is 1012042413329. The next prime is 1012042413377. The reversal of 1012042413331 is 1333142402101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1012042413331 - 21 = 1012042413329 is a prime.
It is a super-2 number, since 2×10120424133312 (a number of 25 digits) contains 22 as substring.
Together with 1012042413329, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1012042413296 and 1012042413305.
It is not a weakly prime, because it can be changed into another prime (1012042413631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506021206665 + 506021206666.
It is an arithmetic number, because the mean of its divisors is an integer number (506021206666).
Almost surely, 21012042413331 is an apocalyptic number.
1012042413331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012042413331 is an equidigital number, since it uses as much as digits as its factorization.
1012042413331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1012042413331 its reverse (1333142402101), we get a palindrome (2345184815432).
The spelling of 1012042413331 in words is "one trillion, twelve billion, forty-two million, four hundred thirteen thousand, three hundred thirty-one".
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