Base | Representation |
---|---|
bin | 11101011101001011111… |
… | …10110001110011001111 |
3 | 10120202102010111100010211 |
4 | 32232211332301303033 |
5 | 113040241103341421 |
6 | 2052541522343251 |
7 | 133056555105121 |
oct | 16564576616317 |
9 | 3522363440124 |
10 | 1012102012111 |
11 | 3602592227a3 |
12 | 14419aabab27 |
13 | 745965c9958 |
14 | 36db381b211 |
15 | 1b4d8e379e1 |
hex | eba5fb1ccf |
1012102012111 has 2 divisors, whose sum is σ = 1012102012112. Its totient is φ = 1012102012110.
The previous prime is 1012102012057. The next prime is 1012102012139. The reversal of 1012102012111 is 1112102012101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1012102012111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1012102012091 and 1012102012100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1012102010111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506051006055 + 506051006056.
It is an arithmetic number, because the mean of its divisors is an integer number (506051006056).
Almost surely, 21012102012111 is an apocalyptic number.
1012102012111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012102012111 is an equidigital number, since it uses as much as digits as its factorization.
1012102012111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 1012102012111 its reverse (1112102012101), we get a palindrome (2124204024212).
The spelling of 1012102012111 in words is "one trillion, twelve billion, one hundred two million, twelve thousand, one hundred eleven".
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