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10121100212143 is a prime number
BaseRepresentation
bin1001001101001000000010…
…0101010011011110101111
31022211120022212122102122201
42103102000211103132233
52311311003123242033
633305322542522331
72063140204225264
oct223220045233657
938746285572581
1010121100212143
113252375238878
121175653b963a7
13585553268c9b
1426dc1462b26b
151284167c247d
hex934809537af

10121100212143 has 2 divisors, whose sum is σ = 10121100212144. Its totient is φ = 10121100212142.

The previous prime is 10121100212099. The next prime is 10121100212159. The reversal of 10121100212143 is 34121200112101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10121100212143 - 225 = 10121066657711 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10121100212143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10121100252143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060550106071 + 5060550106072.

It is an arithmetic number, because the mean of its divisors is an integer number (5060550106072).

Almost surely, 210121100212143 is an apocalyptic number.

10121100212143 is a deficient number, since it is larger than the sum of its proper divisors (1).

10121100212143 is an equidigital number, since it uses as much as digits as its factorization.

10121100212143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 10121100212143 its reverse (34121200112101), we get a palindrome (44242300324244).

The spelling of 10121100212143 in words is "ten trillion, one hundred twenty-one billion, one hundred million, two hundred twelve thousand, one hundred forty-three".