Search a number
-
+
1012124001311 is a prime number
BaseRepresentation
bin11101011101001110100…
…10101010010000011111
310120202110122212111122122
432232213102222100133
5113040312221020221
62052544025533155
7133060243030433
oct16564722522037
93522418774578
101012124001311
1136026a681595
121441a63441bb
137459b028607
1436db67029c3
151b4dad2ceab
hexeba74aa41f

1012124001311 has 2 divisors, whose sum is σ = 1012124001312. Its totient is φ = 1012124001310.

The previous prime is 1012124001283. The next prime is 1012124001313. The reversal of 1012124001311 is 1131004212101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1012124001311 - 226 = 1012056892447 is a prime.

Together with 1012124001313, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1012124001311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1012124001313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506062000655 + 506062000656.

It is an arithmetic number, because the mean of its divisors is an integer number (506062000656).

Almost surely, 21012124001311 is an apocalyptic number.

1012124001311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012124001311 is an equidigital number, since it uses as much as digits as its factorization.

1012124001311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1012124001311 its reverse (1131004212101), we get a palindrome (2143128213412).

The spelling of 1012124001311 in words is "one trillion, twelve billion, one hundred twenty-four million, one thousand, three hundred eleven".