Base | Representation |
---|---|
bin | 10111000000111110011011… |
… | …111010001111001110001000 |
3 | 111021101201221212220000101100 |
4 | 113000332123322033032020 |
5 | 101231410340130000013 |
6 | 555140443445221400 |
7 | 30215025150555564 |
oct | 2700763372171610 |
9 | 437351855800340 |
10 | 101222110000008 |
11 | 2a286068270548 |
12 | b429633a01860 |
13 | 44632862b7c9a |
14 | 1add2679526a4 |
15 | ba80455b6473 |
hex | 5c0f9be8f388 |
101222110000008 has 48 divisors (see below), whose sum is σ = 277446144895920. Its totient is φ = 33334188833376.
The previous prime is 101222109999991. The next prime is 101222110000013. The reversal of 101222110000008 is 800000011222101.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8469046066 + ... + 8469058017.
It is an arithmetic number, because the mean of its divisors is an integer number (5780128018665).
Almost surely, 2101222110000008 is an apocalyptic number.
101222110000008 is a gapful number since it is divisible by the number (18) formed by its first and last digit.
It is an amenable number.
101222110000008 is an abundant number, since it is smaller than the sum of its proper divisors (176224034895912).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
101222110000008 is a wasteful number, since it uses less digits than its factorization.
101222110000008 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16938104178 (or 16938104171 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 18.
Adding to 101222110000008 its reverse (800000011222101), we get a palindrome (901222121222109).
The spelling of 101222110000008 in words is "one hundred one trillion, two hundred twenty-two billion, one hundred ten million, eight", and thus it is an aban number.
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