101222110000013 has 2 divisors, whose sum is σ = 101222110000014. Its totient is φ = 101222110000012.

The previous prime is 101222109999991. The next prime is 101222110000031. The reversal of 101222110000013 is 310000011222101.

Together with next prime (101222110000031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87062746270564 + 14159363729449 = 9330742^2 + 3762893^2 .

It is a cyclic number.

It is not a de Polignac number, because 101222110000013 - 2¹⁴ = 101222109983629 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101222110000093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50611055000006 + 50611055000007.

It is an arithmetic number, because the mean of its divisors is an integer number (50611055000007).

Almost surely, 2^{101222110000013} is an apocalyptic number.

It is an amenable number.

101222110000013 is a deficient number, since it is larger than the sum of its proper divisors (1).

101222110000013 is an equidigital number, since it uses as much as digits as its factorization.

101222110000013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 101222110000013 its reverse (310000011222101), we get a palindrome (411222121222114).

The spelling of 101222110000013 in words is "one hundred one trillion, two hundred twenty-two billion, one hundred ten million, thirteen", and thus it is an aban number.