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101240011102057 is a prime number
BaseRepresentation
bin10111000001001111000110…
…111001100001011101101001
3111021110110011102222012220221
4113001033012321201131221
5101232204020320231212
6555153004040050041
730216230565455512
oct2701170671413551
9437413142865827
10101240011102057
112a292713a44463
12b430baaa63921
134464b79b9c569
141b00085197a09
15ba8741e36807
hex5c13c6e61769

101240011102057 has 2 divisors, whose sum is σ = 101240011102058. Its totient is φ = 101240011102056.

The previous prime is 101240011102003. The next prime is 101240011102063. The reversal of 101240011102057 is 750201110042101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 59170725447001 + 42069285655056 = 7692251^2 + 6486084^2 .

It is an emirp because it is prime and its reverse (750201110042101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101240011102057 - 211 = 101240011100009 is a prime.

It is not a weakly prime, because it can be changed into another prime (101240011102067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50620005551028 + 50620005551029.

It is an arithmetic number, because the mean of its divisors is an integer number (50620005551029).

Almost surely, 2101240011102057 is an apocalyptic number.

It is an amenable number.

101240011102057 is a deficient number, since it is larger than the sum of its proper divisors (1).

101240011102057 is an equidigital number, since it uses as much as digits as its factorization.

101240011102057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 560, while the sum is 25.

Adding to 101240011102057 its reverse (750201110042101), we get a palindrome (851441121144158).

The spelling of 101240011102057 in words is "one hundred one trillion, two hundred forty billion, eleven million, one hundred two thousand, fifty-seven".