1012401413 has 4 divisors (see below), whose sum is σ = 1012465068. Its totient is φ = 1012337760.

The previous prime is 1012401409. The next prime is 1012401427. The reversal of 1012401413 is 3141042101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3141042101 = 47 ⋅66830683.

It can be written as a sum of positive squares in 2 ways, for example, as 107474689 + 904926724 = 10367^2 + 30082^2 .

It is a cyclic number.

It is not a de Polignac number, because 1012401413 - 2² = 1012401409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1012401391 and 1012401400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1012401113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14795 + ... + 47367.

It is an arithmetic number, because the mean of its divisors is an integer number (253116267).

Almost surely, 2^1012401413 is an apocalyptic number.

It is an amenable number.

1012401413 is a deficient number, since it is larger than the sum of its proper divisors (63655).

1012401413 is an equidigital number, since it uses as much as digits as its factorization.

1012401413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63654.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 1012401413 is about 31818.2559704331. The cubic root of 1012401413 is about 1004.1168327635.

Adding to 1012401413 its reverse (3141042101), we get a palindrome (4153443514).

The spelling of 1012401413 in words is "one billion, twelve million, four hundred one thousand, four hundred thirteen".