Base | Representation |
---|---|
bin | 10010110111100101… |
… | …11011010010100111 |
3 | 222010222101220002211 |
4 | 21123302323102213 |
5 | 131221240330203 |
6 | 4353105144251 |
7 | 506013450436 |
oct | 113362732247 |
9 | 28128356084 |
10 | 10130011303 |
11 | 4329144475 |
12 | 1b6862b087 |
13 | c5590b139 |
14 | 6c152711d |
15 | 3e44dec6d |
hex | 25bcbb4a7 |
10130011303 has 2 divisors, whose sum is σ = 10130011304. Its totient is φ = 10130011302.
The previous prime is 10130011277. The next prime is 10130011343. The reversal of 10130011303 is 30311003101.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10130011303 - 29 = 10130010791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10130011343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065005651 + 5065005652.
It is an arithmetic number, because the mean of its divisors is an integer number (5065005652).
Almost surely, 210130011303 is an apocalyptic number.
10130011303 is a deficient number, since it is larger than the sum of its proper divisors (1).
10130011303 is an equidigital number, since it uses as much as digits as its factorization.
10130011303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27, while the sum is 13.
Adding to 10130011303 its reverse (30311003101), we get a palindrome (40441014404).
The spelling of 10130011303 in words is "ten billion, one hundred thirty million, eleven thousand, three hundred three".
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