Base | Representation |
---|---|
bin | 1001001101101001001110… |
… | …1110011011001111001111 |
3 | 1022212102022220102211212121 |
4 | 2103122103232123033033 |
5 | 2311432230343224121 |
6 | 33313355110313411 |
7 | 2063604060244501 |
oct | 223322356331717 |
9 | 38772286384777 |
10 | 10130011304911 |
11 | 3256128324753 |
12 | 1177320358867 |
13 | 58634348a844 |
14 | 27041bcdbd71 |
15 | 128788c8b141 |
hex | 93693b9b3cf |
10130011304911 has 2 divisors, whose sum is σ = 10130011304912. Its totient is φ = 10130011304910.
The previous prime is 10130011304899. The next prime is 10130011304953. The reversal of 10130011304911 is 11940311003101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10130011304911 - 211 = 10130011302863 is a prime.
It is a super-2 number, since 2×101300113049112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10130011304981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065005652455 + 5065005652456.
It is an arithmetic number, because the mean of its divisors is an integer number (5065005652456).
Almost surely, 210130011304911 is an apocalyptic number.
10130011304911 is a deficient number, since it is larger than the sum of its proper divisors (1).
10130011304911 is an equidigital number, since it uses as much as digits as its factorization.
10130011304911 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 25.
The spelling of 10130011304911 in words is "ten trillion, one hundred thirty billion, eleven million, three hundred four thousand, nine hundred eleven".
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