Base | Representation |
---|---|
bin | 101111001010111111… |
… | …0000001110101000001 |
3 | 100200110210102002220121 |
4 | 1132111332001311001 |
5 | 3124430340012114 |
6 | 114311533140241 |
7 | 10214213312461 |
oct | 1362576016501 |
9 | 320423362817 |
10 | 101300313409 |
11 | 39a63427889 |
12 | 1777132a681 |
13 | 9725027269 |
14 | 4c8da23ba1 |
15 | 297d48ca24 |
hex | 1795f81d41 |
101300313409 has 2 divisors, whose sum is σ = 101300313410. Its totient is φ = 101300313408.
The previous prime is 101300313383. The next prime is 101300313431. The reversal of 101300313409 is 904313003101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 79949259009 + 21351054400 = 282753^2 + 146120^2 .
It is an emirp because it is prime and its reverse (904313003101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101300313409 - 25 = 101300313377 is a prime.
It is not a weakly prime, because it can be changed into another prime (101300313469) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50650156704 + 50650156705.
It is an arithmetic number, because the mean of its divisors is an integer number (50650156705).
Almost surely, 2101300313409 is an apocalyptic number.
It is an amenable number.
101300313409 is a deficient number, since it is larger than the sum of its proper divisors (1).
101300313409 is an equidigital number, since it uses as much as digits as its factorization.
101300313409 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 101300313409 in words is "one hundred one billion, three hundred million, three hundred thirteen thousand, four hundred nine".
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