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101300313409 is a prime number
BaseRepresentation
bin101111001010111111…
…0000001110101000001
3100200110210102002220121
41132111332001311001
53124430340012114
6114311533140241
710214213312461
oct1362576016501
9320423362817
10101300313409
1139a63427889
121777132a681
139725027269
144c8da23ba1
15297d48ca24
hex1795f81d41

101300313409 has 2 divisors, whose sum is σ = 101300313410. Its totient is φ = 101300313408.

The previous prime is 101300313383. The next prime is 101300313431. The reversal of 101300313409 is 904313003101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79949259009 + 21351054400 = 282753^2 + 146120^2 .

It is an emirp because it is prime and its reverse (904313003101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101300313409 - 25 = 101300313377 is a prime.

It is not a weakly prime, because it can be changed into another prime (101300313469) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50650156704 + 50650156705.

It is an arithmetic number, because the mean of its divisors is an integer number (50650156705).

Almost surely, 2101300313409 is an apocalyptic number.

It is an amenable number.

101300313409 is a deficient number, since it is larger than the sum of its proper divisors (1).

101300313409 is an equidigital number, since it uses as much as digits as its factorization.

101300313409 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

The spelling of 101300313409 in words is "one hundred one billion, three hundred million, three hundred thirteen thousand, four hundred nine".