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10130033101031 is a prime number
BaseRepresentation
bin1001001101101001010100…
…0001100100100011100111
31022212102101102110012112022
42103122111001210203213
52311432301433213111
633313401205413355
72063604443434154
oct223322501444347
938772342405468
1010130033101031
113256139661478
12117732770a25b
13586347b4c65c
14270420b7322b
1512878ab442db
hex936950648e7

10130033101031 has 2 divisors, whose sum is σ = 10130033101032. Its totient is φ = 10130033101030.

The previous prime is 10130033100983. The next prime is 10130033101033. The reversal of 10130033101031 is 13010133003101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10130033101031 is a prime.

It is a super-2 number, since 2×101300331010312 (a number of 27 digits) contains 22 as substring.

Together with 10130033101033, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10130033101033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065016550515 + 5065016550516.

It is an arithmetic number, because the mean of its divisors is an integer number (5065016550516).

Almost surely, 210130033101031 is an apocalyptic number.

10130033101031 is a deficient number, since it is larger than the sum of its proper divisors (1).

10130033101031 is an equidigital number, since it uses as much as digits as its factorization.

10130033101031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 10130033101031 its reverse (13010133003101), we get a palindrome (23140166104132).

The spelling of 10130033101031 in words is "ten trillion, one hundred thirty billion, thirty-three million, one hundred one thousand, thirty-one".