1013020031 has 2 divisors, whose sum is σ = 1013020032. Its totient is φ = 1013020030.

The previous prime is 1013019991. The next prime is 1013020033. The reversal of 1013020031 is 1300203101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1013020031 is a prime.

It is a super-2 number, since 2×1013020031² = 2052419166414481922, which contains 22 as substring.

Together with 1013020033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1013019994 and 1013020021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1013020033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506510015 + 506510016.

It is an arithmetic number, because the mean of its divisors is an integer number (506510016).

Almost surely, 2^1013020031 is an apocalyptic number.

1013020031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013020031 is an equidigital number, since it uses as much as digits as its factorization.

1013020031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 1013020031 is about 31827.9756032331. The cubic root of 1013020031 is about 1004.3213097174.

Adding to 1013020031 its reverse (1300203101), we get a palindrome (2313223132).

The spelling of 1013020031 in words is "one billion, thirteen million, twenty thousand, thirty-one".