101304310031 has 2 divisors, whose sum is σ = 101304310032. Its totient is φ = 101304310030.

The previous prime is 101304310027. The next prime is 101304310033. The reversal of 101304310031 is 130013403101.

It is a strong prime.

It is an emirp because it is prime and its reverse (130013403101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101304310031 - 2² = 101304310027 is a prime.

It is a super-2 number, since 2×101304310031² (a number of 23 digits) contains 22 as substring.

Together with 101304310033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101304309991 and 101304310009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101304310033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50652155015 + 50652155016.

It is an arithmetic number, because the mean of its divisors is an integer number (50652155016).

Almost surely, 2^101304310031 is an apocalyptic number.

101304310031 is a deficient number, since it is larger than the sum of its proper divisors (1).

101304310031 is an equidigital number, since it uses as much as digits as its factorization.

101304310031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 101304310031 its reverse (130013403101), we get a palindrome (231317713132).

The spelling of 101304310031 in words is "one hundred one billion, three hundred four million, three hundred ten thousand, thirty-one".