Base | Representation |
---|---|
bin | 11101011111000101010… |
… | …11101111010001000010 |
3 | 10120212001002211101110020 |
4 | 32233202223233101002 |
5 | 113044332312244140 |
6 | 2053230542514310 |
7 | 133124032401651 |
oct | 16574253572102 |
9 | 3525032741406 |
10 | 1013120431170 |
11 | 360731087041 |
12 | 144423b95996 |
13 | 746c95b5793 |
14 | 3706cba1198 |
15 | 1b5485566d0 |
hex | ebe2aef442 |
1013120431170 has 16 divisors (see below), whose sum is σ = 2431489034880. Its totient is φ = 270165448304.
The previous prime is 1013120431153. The next prime is 1013120431171. The reversal of 1013120431170 is 711340213101.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 1013120431170.
It is not an unprimeable number, because it can be changed into a prime (1013120431171) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16885340490 + ... + 16885340549.
It is an arithmetic number, because the mean of its divisors is an integer number (151968064680).
Almost surely, 21013120431170 is an apocalyptic number.
1013120431170 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1013120431170 is an abundant number, since it is smaller than the sum of its proper divisors (1418368603710).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1013120431170 is a wasteful number, since it uses less digits than its factorization.
1013120431170 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33770681049.
The product of its (nonzero) digits is 504, while the sum is 24.
Adding to 1013120431170 its reverse (711340213101), we get a palindrome (1724460644271).
The spelling of 1013120431170 in words is "one trillion, thirteen billion, one hundred twenty million, four hundred thirty-one thousand, one hundred seventy".
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