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101312111 is a prime number
BaseRepresentation
bin1100000100111…
…10011001101111
321001122012002102
412002132121233
5201413441421
614015245315
72340065405
oct602363157
9231565072
10101312111
115220831a
1229b1983b
1317cb2ac4
14d653475
158d6360b
hex609e66f

101312111 has 2 divisors, whose sum is σ = 101312112. Its totient is φ = 101312110.

The previous prime is 101312093. The next prime is 101312117. The reversal of 101312111 is 111213101.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (111213101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101312111 - 210 = 101311087 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101312092 and 101312101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101312117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50656055 + 50656056.

It is an arithmetic number, because the mean of its divisors is an integer number (50656056).

Almost surely, 2101312111 is an apocalyptic number.

101312111 is a deficient number, since it is larger than the sum of its proper divisors (1).

101312111 is an equidigital number, since it uses as much as digits as its factorization.

101312111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 11.

The square root of 101312111 is about 10065.3917459779. The cubic root of 101312111 is about 466.1801617539.

Adding to 101312111 its reverse (111213101), we get a palindrome (212525212).

The spelling of 101312111 in words is "one hundred one million, three hundred twelve thousand, one hundred eleven".