Base | Representation |
---|---|
bin | 1001001101101110011011… |
… | …0000101111111111100111 |
3 | 1022212112220222211120211011 |
4 | 2103123212300233333213 |
5 | 2311443104013020033 |
6 | 33314145233523051 |
7 | 2063653434455623 |
oct | 223334660577747 |
9 | 38775828746734 |
10 | 10131404423143 |
11 | 3256782743033 |
12 | 117764aa13487 |
13 | 586505c99b63 |
14 | 270510d3c183 |
15 | 12881b221ccd |
hex | 936e6c2ffe7 |
10131404423143 has 2 divisors, whose sum is σ = 10131404423144. Its totient is φ = 10131404423142.
The previous prime is 10131404423141. The next prime is 10131404423243. The reversal of 10131404423143 is 34132440413101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10131404423143 - 21 = 10131404423141 is a prime.
Together with 10131404423141, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10131404423141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065702211571 + 5065702211572.
It is an arithmetic number, because the mean of its divisors is an integer number (5065702211572).
Almost surely, 210131404423143 is an apocalyptic number.
10131404423143 is a deficient number, since it is larger than the sum of its proper divisors (1).
10131404423143 is an equidigital number, since it uses as much as digits as its factorization.
10131404423143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 10131404423143 its reverse (34132440413101), we get a palindrome (44263844836244).
The spelling of 10131404423143 in words is "ten trillion, one hundred thirty-one billion, four hundred four million, four hundred twenty-three thousand, one hundred forty-three".
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