Base | Representation |
---|---|
bin | 1001001101110000110101… |
… | …1100100110111111001111 |
3 | 1022212121121020002210212122 |
4 | 2103130031130212333033 |
5 | 2312000421141023144 |
6 | 33314333500523155 |
7 | 2064005505240323 |
oct | 223341534467717 |
9 | 38777536083778 |
10 | 10132053454799 |
11 | 3256a86040131 |
12 | 11777b02504bb |
13 | 5865aa5a2163 |
14 | 270573209983 |
15 | 1288581c77ee |
hex | 9370d726fcf |
10132053454799 has 2 divisors, whose sum is σ = 10132053454800. Its totient is φ = 10132053454798.
The previous prime is 10132053454769. The next prime is 10132053454891. The reversal of 10132053454799 is 99745435023101.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10132053454799 is a prime.
It is a super-2 number, since 2×101320534547992 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 10132053454799.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10132053454709) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066026727399 + 5066026727400.
It is an arithmetic number, because the mean of its divisors is an integer number (5066026727400).
Almost surely, 210132053454799 is an apocalyptic number.
10132053454799 is a deficient number, since it is larger than the sum of its proper divisors (1).
10132053454799 is an equidigital number, since it uses as much as digits as its factorization.
10132053454799 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4082400, while the sum is 53.
The spelling of 10132053454799 in words is "ten trillion, one hundred thirty-two billion, fifty-three million, four hundred fifty-four thousand, seven hundred ninety-nine".
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