Base | Representation |
---|---|
bin | 101111001011111010… |
… | …0001110111010001101 |
3 | 100200112221201101111102 |
4 | 1132113310032322031 |
5 | 3130011303044411 |
6 | 114315001232445 |
7 | 10215040560362 |
oct | 1362764167215 |
9 | 320487641442 |
10 | 101331299981 |
11 | 39a7997151a |
12 | 1777b792725 |
13 | 972b586302 |
14 | 4c93bac469 |
15 | 298105dd3b |
hex | 1797d0ee8d |
101331299981 has 2 divisors, whose sum is σ = 101331299982. Its totient is φ = 101331299980.
The previous prime is 101331299929. The next prime is 101331300047. The reversal of 101331299981 is 189992133101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 79594515625 + 21736784356 = 282125^2 + 147434^2 .
It is a cyclic number.
It is not a de Polignac number, because 101331299981 - 218 = 101331037837 is a prime.
It is a super-2 number, since 2×1013312999812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101331299081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50665649990 + 50665649991.
It is an arithmetic number, because the mean of its divisors is an integer number (50665649991).
Almost surely, 2101331299981 is an apocalyptic number.
It is an amenable number.
101331299981 is a deficient number, since it is larger than the sum of its proper divisors (1).
101331299981 is an equidigital number, since it uses as much as digits as its factorization.
101331299981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 104976, while the sum is 47.
The spelling of 101331299981 in words is "one hundred one billion, three hundred thirty-one million, two hundred ninety-nine thousand, nine hundred eighty-one".
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