Base | Representation |
---|---|
bin | 101111001100001010… |
… | …1111101011100000111 |
3 | 100200120120100120112101 |
4 | 1132120111331130013 |
5 | 3130021034010234 |
6 | 114315514532531 |
7 | 10215205663024 |
oct | 1363025753407 |
9 | 320516316471 |
10 | 101340141319 |
11 | 39a8396010a |
12 | 17782737147 |
13 | 9730360681 |
14 | 4c9503054b |
15 | 2981c08814 |
hex | 179857d707 |
101340141319 has 2 divisors, whose sum is σ = 101340141320. Its totient is φ = 101340141318.
The previous prime is 101340141271. The next prime is 101340141347. The reversal of 101340141319 is 913141043101.
It is an a-pointer prime, because the next prime (101340141347) can be obtained adding 101340141319 to its sum of digits (28).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101340141319 - 29 = 101340140807 is a prime.
It is a super-2 number, since 2×1013401413192 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101340141349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50670070659 + 50670070660.
It is an arithmetic number, because the mean of its divisors is an integer number (50670070660).
Almost surely, 2101340141319 is an apocalyptic number.
101340141319 is a deficient number, since it is larger than the sum of its proper divisors (1).
101340141319 is an equidigital number, since it uses as much as digits as its factorization.
101340141319 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 28.
The spelling of 101340141319 in words is "one hundred one billion, three hundred forty million, one hundred forty-one thousand, three hundred nineteen".
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