1013425117 has 2 divisors, whose sum is σ = 1013425118. Its totient is φ = 1013425116.

The previous prime is 1013425087. The next prime is 1013425151. The reversal of 1013425117 is 7115243101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 999444996 + 13980121 = 31614^2 + 3739^2 .

It is a cyclic number.

It is not a de Polignac number, because 1013425117 - 2¹⁹ = 1012900829 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1013425091 and 1013425100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1013425187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506712558 + 506712559.

It is an arithmetic number, because the mean of its divisors is an integer number (506712559).

Almost surely, 2^1013425117 is an apocalyptic number.

It is an amenable number.

1013425117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013425117 is an equidigital number, since it uses as much as digits as its factorization.

1013425117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 25.

The square root of 1013425117 is about 31834.3386455569. The cubic root of 1013425117 is about 1004.4551610639.

Adding to 1013425117 its reverse (7115243101), we get a palindrome (8128668218).

The spelling of 1013425117 in words is "one billion, thirteen million, four hundred twenty-five thousand, one hundred seventeen".