1013440301 has 2 divisors, whose sum is σ = 1013440302. Its totient is φ = 1013440300.

The previous prime is 1013440289. The next prime is 1013440303. The reversal of 1013440301 is 1030443101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 690375625 + 323064676 = 26275^2 + 17974^2 .

It is a cyclic number.

It is not a de Polignac number, because 1013440301 - 2¹⁰ = 1013439277 is a prime.

It is a super-2 number, since 2×1013440301² = 2054122487381941202, which contains 22 as substring.

Together with 1013440303, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1013440301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1013440303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506720150 + 506720151.

It is an arithmetic number, because the mean of its divisors is an integer number (506720151).

Almost surely, 2^1013440301 is an apocalyptic number.

It is an amenable number.

1013440301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013440301 is an equidigital number, since it uses as much as digits as its factorization.

1013440301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1013440301 is about 31834.5771292788. The cubic root of 1013440301 is about 1004.4601775736.

Adding to 1013440301 its reverse (1030443101), we get a palindrome (2043883402).

The spelling of 1013440301 in words is "one billion, thirteen million, four hundred forty thousand, three hundred one".