Base | Representation |
---|---|
bin | 11101011111101100111… |
… | …10011110110100011101 |
3 | 10120212220020200020121011 |
4 | 32233312132132310131 |
5 | 113101022320002003 |
6 | 2053323524135221 |
7 | 133135204055254 |
oct | 16576636366435 |
9 | 3525806606534 |
10 | 1013452500253 |
11 | 3608915744a6 |
12 | 1444b7237511 |
13 | 7475033126b |
14 | 370a0d2179b |
15 | 1b56779c46d |
hex | ebf679ed1d |
1013452500253 has 2 divisors, whose sum is σ = 1013452500254. Its totient is φ = 1013452500252.
The previous prime is 1013452500251. The next prime is 1013452500293. The reversal of 1013452500253 is 3520052543101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1013448916804 + 3583449 = 1006702^2 + 1893^2 .
It is an emirp because it is prime and its reverse (3520052543101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1013452500253 - 21 = 1013452500251 is a prime.
Together with 1013452500251, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1013452500251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506726250126 + 506726250127.
It is an arithmetic number, because the mean of its divisors is an integer number (506726250127).
Almost surely, 21013452500253 is an apocalyptic number.
It is an amenable number.
1013452500253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013452500253 is an equidigital number, since it uses as much as digits as its factorization.
1013452500253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 1013452500253 in words is "one trillion, thirteen billion, four hundred fifty-two million, five hundred thousand, two hundred fifty-three".
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