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10136993650 = 252728962839
BaseRepresentation
bin10010111000011011…
…00011111101110010
3222011110112122002021
421130031203331302
5131230032244100
64353514542054
7506130011230
oct113415437562
928143478067
1010136993650
114332083403
121b6aa3792a
13c571b42c4
146c2423950
153e4e1da1a
hex25c363f72

10136993650 has 24 divisors (see below), whose sum is σ = 21548352960. Its totient is φ = 3475540560.

The previous prime is 10136993641. The next prime is 10136993653. The reversal of 10136993650 is 5639963101.

It is a junction number, because it is equal to n+sod(n) for n = 10136993597 and 10136993606.

It is not an unprimeable number, because it can be changed into a prime (10136993653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 14481070 + ... + 14481769.

It is an arithmetic number, because the mean of its divisors is an integer number (897848040).

Almost surely, 210136993650 is an apocalyptic number.

10136993650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

10136993650 is an abundant number, since it is smaller than the sum of its proper divisors (11411359310).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10136993650 is a wasteful number, since it uses less digits than its factorization.

10136993650 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28962858 (or 28962853 counting only the distinct ones).

The product of its (nonzero) digits is 131220, while the sum is 43.

The spelling of 10136993650 in words is "ten billion, one hundred thirty-six million, nine hundred ninety-three thousand, six hundred fifty".

Divisors: 1 2 5 7 10 14 25 35 50 70 175 350 28962839 57925678 144814195 202739873 289628390 405479746 724070975 1013699365 1448141950 2027398730 5068496825 10136993650