Base | Representation |
---|---|
bin | 10010111000110000… |
… | …11110101001010101 |
3 | 222011122221000201200 |
4 | 21130120132221111 |
5 | 131231300333240 |
6 | 4354100143113 |
7 | 506163230526 |
oct | 113430365125 |
9 | 28148830650 |
10 | 10139855445 |
11 | 4333758525 |
12 | 1b6b997a99 |
13 | c57976a85 |
14 | 6c296a84d |
15 | 3e52d6930 |
hex | 25c61ea55 |
10139855445 has 54 divisors (see below), whose sum is σ = 18691601058. Its totient is φ = 5084045568.
The previous prime is 10139855311. The next prime is 10139855489. The reversal of 10139855445 is 54455893101.
It is a happy number.
10139855445 is a `hidden beast` number, since 1 + 0 + 1 + 3 + 98 + 554 + 4 + 5 = 666.
10139855445 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 3 ways, for example, as 3396325284 + 6743530161 = 58278^2 + 82119^2 .
It is not a de Polignac number, because 10139855445 - 213 = 10139847253 is a prime.
It is a super-2 number, since 2×101398554452 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a self number, because there is not a number n which added to its sum of digits gives 10139855445.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 53 ways as a sum of consecutive naturals, for example, 11482974 + ... + 11483856.
Almost surely, 210139855445 is an apocalyptic number.
10139855445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
10139855445 is a deficient number, since it is larger than the sum of its proper divisors (8551745613).
10139855445 is an frugal number, since it uses more digits than its factorization.
10139855445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1811 (or 908 counting only the distinct ones).
The product of its (nonzero) digits is 432000, while the sum is 45.
Multiplying 10139855445 by its sum of digits (45), we get a square (456293495025 = 6754952).
10139855445 divided by its sum of digits (45) gives a square (225330121 = 150112).
The spelling of 10139855445 in words is "ten billion, one hundred thirty-nine million, eight hundred fifty-five thousand, four hundred forty-five".
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