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101404033040113 is a prime number
BaseRepresentation
bin10111000011100111110111…
…010111100011111011110001
3111022001010112102011222201121
4113003213313113203323301
5101242400424424240423
6555400211503302241
730234125320105606
oct2703476727437361
9438033472158647
10101404033040113
112a346233065171
12b4589455aa981
13447748946c18b
141b07da4cd26ad
15bacb41a2e45d
hex5c39f75e3ef1

101404033040113 has 2 divisors, whose sum is σ = 101404033040114. Its totient is φ = 101404033040112.

The previous prime is 101404033040087. The next prime is 101404033040147. The reversal of 101404033040113 is 311040330404101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100698957102769 + 705075937344 = 10034887^2 + 839688^2 .

It is a cyclic number.

It is not a de Polignac number, because 101404033040113 - 221 = 101404030942961 is a prime.

It is not a weakly prime, because it can be changed into another prime (101404033047113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50702016520056 + 50702016520057.

It is an arithmetic number, because the mean of its divisors is an integer number (50702016520057).

Almost surely, 2101404033040113 is an apocalyptic number.

It is an amenable number.

101404033040113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101404033040113 is an equidigital number, since it uses as much as digits as its factorization.

101404033040113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 101404033040113 its reverse (311040330404101), we get a palindrome (412444363444214).

The spelling of 101404033040113 in words is "one hundred one trillion, four hundred four billion, thirty-three million, forty thousand, one hundred thirteen".