Base | Representation |
---|---|
bin | 10111000011101001110011… |
… | …010010100110001011101111 |
3 | 111022001022220022022212002121 |
4 | 113003221303102212023233 |
5 | 101242414204200112031 |
6 | 555401154053133411 |
7 | 30234230663664001 |
oct | 2703516322461357 |
9 | 438038808285077 |
10 | 101406112113391 |
11 | 2a3470aa6aa748 |
12 | b45922592a267 |
13 | 447772b110b57 |
14 | 1b08121092371 |
15 | bacc14311011 |
hex | 5c3a734a62ef |
101406112113391 has 2 divisors, whose sum is σ = 101406112113392. Its totient is φ = 101406112113390.
The previous prime is 101406112113377. The next prime is 101406112113409. The reversal of 101406112113391 is 193311211604101.
It is a weak prime.
It is an emirp because it is prime and its reverse (193311211604101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101406112113391 - 241 = 99207088857839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101406112113301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50703056056695 + 50703056056696.
It is an arithmetic number, because the mean of its divisors is an integer number (50703056056696).
Almost surely, 2101406112113391 is an apocalyptic number.
101406112113391 is a deficient number, since it is larger than the sum of its proper divisors (1).
101406112113391 is an equidigital number, since it uses as much as digits as its factorization.
101406112113391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 34.
Adding to 101406112113391 its reverse (193311211604101), we get a palindrome (294717323717492).
The spelling of 101406112113391 in words is "one hundred one trillion, four hundred six billion, one hundred twelve million, one hundred thirteen thousand, three hundred ninety-one".
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