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10141304713 is a prime number
BaseRepresentation
bin10010111000111100…
…00000011110001001
3222011202122122202021
421130132000132021
5131232133222323
64354151204441
7506211445021
oct113436003611
928152578667
1010141304713
114334558371
121b70376721
13c58063627
146c2c26a81
153e54c105d
hex25c780789

10141304713 has 2 divisors, whose sum is σ = 10141304714. Its totient is φ = 10141304712.

The previous prime is 10141304699. The next prime is 10141304741. The reversal of 10141304713 is 31740314101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8105761024 + 2035543689 = 90032^2 + 45117^2 .

It is a cyclic number.

It is not a de Polignac number, because 10141304713 - 25 = 10141304681 is a prime.

It is a super-2 number, since 2×101413047132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10141304783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5070652356 + 5070652357.

It is an arithmetic number, because the mean of its divisors is an integer number (5070652357).

Almost surely, 210141304713 is an apocalyptic number.

It is an amenable number.

10141304713 is a deficient number, since it is larger than the sum of its proper divisors (1).

10141304713 is an equidigital number, since it uses as much as digits as its factorization.

10141304713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 10141304713 its reverse (31740314101), we get a palindrome (41881618814).

The spelling of 10141304713 in words is "ten billion, one hundred forty-one million, three hundred four thousand, seven hundred thirteen".