Base | Representation |
---|---|
bin | 11101100001010011010… |
… | …10010000010001111111 |
3 | 10120222010002111221201221 |
4 | 32300221222100101333 |
5 | 113104302133140242 |
6 | 2053545041414211 |
7 | 133165402103323 |
oct | 16605152202177 |
9 | 3528102457657 |
10 | 1014311224447 |
11 | 361192274714 |
12 | 1446b693a367 |
13 | 748592054a1 |
14 | 37142db5983 |
15 | 1b5b7d74167 |
hex | ec29a9047f |
1014311224447 has 2 divisors, whose sum is σ = 1014311224448. Its totient is φ = 1014311224446.
The previous prime is 1014311224417. The next prime is 1014311224457. The reversal of 1014311224447 is 7444221134101.
1014311224447 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (7444221134101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1014311224447 - 27 = 1014311224319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1014311224417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507155612223 + 507155612224.
It is an arithmetic number, because the mean of its divisors is an integer number (507155612224).
Almost surely, 21014311224447 is an apocalyptic number.
1014311224447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1014311224447 is an equidigital number, since it uses as much as digits as its factorization.
1014311224447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 34.
Adding to 1014311224447 its reverse (7444221134101), we get a palindrome (8458532358548).
The spelling of 1014311224447 in words is "one trillion, fourteen billion, three hundred eleven million, two hundred twenty-four thousand, four hundred forty-seven".
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