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10143120041 is a prime number
BaseRepresentation
bin10010111001001001…
…11011101010101001
3222011220001212220122
421130210323222221
5131233114320131
64354254133025
7506233045355
oct113444735251
928156055818
1010143120041
11433558823a
121b70ab1175
13c5854a9a2
146c317a465
153e572dd7b
hex25c93baa9

10143120041 has 2 divisors, whose sum is σ = 10143120042. Its totient is φ = 10143120040.

The previous prime is 10143119963. The next prime is 10143120067. The reversal of 10143120041 is 14002134101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8543120041 + 1600000000 = 92429^2 + 40000^2 .

It is an emirp because it is prime and its reverse (14002134101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10143120041 is a prime.

It is a super-2 number, since 2×101431200412 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10143123041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071560020 + 5071560021.

It is an arithmetic number, because the mean of its divisors is an integer number (5071560021).

Almost surely, 210143120041 is an apocalyptic number.

It is an amenable number.

10143120041 is a deficient number, since it is larger than the sum of its proper divisors (1).

10143120041 is an equidigital number, since it uses as much as digits as its factorization.

10143120041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 10143120041 its reverse (14002134101), we get a palindrome (24145254142).

The spelling of 10143120041 in words is "ten billion, one hundred forty-three million, one hundred twenty thousand, forty-one".