10143223117 has 2 divisors, whose sum is σ = 10143223118. Its totient is φ = 10143223116.

The previous prime is 10143223067. The next prime is 10143223133. The reversal of 10143223117 is 71132234101.

10143223117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6116178436 + 4027044681 = 78206^2 + 63459^2 .

It is an emirp because it is prime and its reverse (71132234101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10143223117 - 2⁷ = 10143222989 is a prime.

It is a super-4 number, since 4×10143223117⁴ (a number of 41 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10143223091 and 10143223100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10143223147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071611558 + 5071611559.

It is an arithmetic number, because the mean of its divisors is an integer number (5071611559).

Almost surely, 2^10143223117 is an apocalyptic number.

It is an amenable number.

10143223117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10143223117 is an equidigital number, since it uses as much as digits as its factorization.

10143223117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 10143223117 its reverse (71132234101), we get a palindrome (81275457218).

The spelling of 10143223117 in words is "ten billion, one hundred forty-three million, two hundred twenty-three thousand, one hundred seventeen".