101440121 has 2 divisors, whose sum is σ = 101440122. Its totient is φ = 101440120.

The previous prime is 101440111. The next prime is 101440123. The reversal of 101440121 is 121044101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101284096 + 156025 = 10064^2 + 395^2 .

It is a cyclic number.

It is not a de Polignac number, because 101440121 - 2¹⁸ = 101177977 is a prime.

Together with 101440123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101440096 and 101440105.

It is not a weakly prime, because it can be changed into another prime (101440123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50720060 + 50720061.

It is an arithmetic number, because the mean of its divisors is an integer number (50720061).

Almost surely, 2^101440121 is an apocalyptic number.

It is an amenable number.

101440121 is a deficient number, since it is larger than the sum of its proper divisors (1).

101440121 is an equidigital number, since it uses as much as digits as its factorization.

101440121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32, while the sum is 14.

The square root of 101440121 is about 10071.7486565144. The cubic root of 101440121 is about 466.3764219565.

Adding to 101440121 its reverse (121044101), we get a palindrome (222484222).

The spelling of 101440121 in words is "one hundred one million, four hundred forty thousand, one hundred twenty-one".