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10144023014231 is a prime number
BaseRepresentation
bin1001001110011101011011…
…1000110110101101010111
31022220202111101221102121122
42103213112320312231113
52312144424342423411
633324033322034155
72064611226642131
oct223472670665527
938822441842548
1010144023014231
1132610685a0307
121179b9094895b
135877673392c2
14270d8ab82051
15128d08e339db
hex939d6e36b57

10144023014231 has 2 divisors, whose sum is σ = 10144023014232. Its totient is φ = 10144023014230.

The previous prime is 10144023014201. The next prime is 10144023014233. The reversal of 10144023014231 is 13241032044101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10144023014231 is a prime.

It is a super-2 number, since 2×101440230142312 (a number of 27 digits) contains 22 as substring.

Together with 10144023014233, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10144023014231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10144023014233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5072011507115 + 5072011507116.

It is an arithmetic number, because the mean of its divisors is an integer number (5072011507116).

Almost surely, 210144023014231 is an apocalyptic number.

10144023014231 is a deficient number, since it is larger than the sum of its proper divisors (1).

10144023014231 is an equidigital number, since it uses as much as digits as its factorization.

10144023014231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 10144023014231 its reverse (13241032044101), we get a palindrome (23385055058332).

The spelling of 10144023014231 in words is "ten trillion, one hundred forty-four billion, twenty-three million, fourteen thousand, two hundred thirty-one".