Base | Representation |
---|---|
bin | 10010111001010001… |
… | …10011101001000111 |
3 | 222011221222111012112 |
4 | 21130220303221013 |
5 | 131233344321001 |
6 | 4354332011235 |
7 | 506244505541 |
oct | 113450635107 |
9 | 28157874175 |
10 | 10144135751 |
11 | 4336111372 |
12 | 1b71300b1b |
13 | c588150b9 |
14 | 6c3362691 |
15 | 3e587ecbb |
hex | 25ca33a47 |
10144135751 has 2 divisors, whose sum is σ = 10144135752. Its totient is φ = 10144135750.
The previous prime is 10144135723. The next prime is 10144135787. The reversal of 10144135751 is 15753144101.
10144135751 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (15753144101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10144135751 - 222 = 10139941447 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10144135951) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5072067875 + 5072067876.
It is an arithmetic number, because the mean of its divisors is an integer number (5072067876).
Almost surely, 210144135751 is an apocalyptic number.
10144135751 is a deficient number, since it is larger than the sum of its proper divisors (1).
10144135751 is an equidigital number, since it uses as much as digits as its factorization.
10144135751 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8400, while the sum is 32.
Adding to 10144135751 its reverse (15753144101), we get a palindrome (25897279852).
The spelling of 10144135751 in words is "ten billion, one hundred forty-four million, one hundred thirty-five thousand, seven hundred fifty-one".
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