Base | Representation |
---|---|
bin | 1100000101111… |
… | …10001001000001 |
3 | 21001212210102022 |
4 | 12002332021001 |
5 | 201432121423 |
6 | 14022131225 |
7 | 2341146413 |
oct | 602761101 |
9 | 231783368 |
10 | 101442113 |
11 | 52296a63 |
12 | 29b80b15 |
13 | 1802a026 |
14 | d6889b3 |
15 | 8d8bdc8 |
hex | 60be241 |
101442113 has 2 divisors, whose sum is σ = 101442114. Its totient is φ = 101442112.
The previous prime is 101442097. The next prime is 101442119. The reversal of 101442113 is 311244101.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 54272689 + 47169424 = 7367^2 + 6868^2 .
It is a cyclic number.
It is not a de Polignac number, because 101442113 - 24 = 101442097 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101442091 and 101442100.
It is not a weakly prime, because it can be changed into another prime (101442119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50721056 + 50721057.
It is an arithmetic number, because the mean of its divisors is an integer number (50721057).
Almost surely, 2101442113 is an apocalyptic number.
It is an amenable number.
101442113 is a deficient number, since it is larger than the sum of its proper divisors (1).
101442113 is an equidigital number, since it uses as much as digits as its factorization.
101442113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
The square root of 101442113 is about 10071.8475465031. The cubic root of 101442113 is about 466.3794747123.
Adding to 101442113 its reverse (311244101), we get a palindrome (412686214).
The spelling of 101442113 in words is "one hundred one million, four hundred forty-two thousand, one hundred thirteen".
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