101443124401 has 2 divisors, whose sum is σ = 101443124402. Its totient is φ = 101443124400.

The previous prime is 101443124399. The next prime is 101443124423. The reversal of 101443124401 is 104421344101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82475224225 + 18967900176 = 287185^2 + 137724^2 .

It is an emirp because it is prime and its reverse (104421344101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101443124401 - 2¹ = 101443124399 is a prime.

Together with 101443124399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (101443124441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50721562200 + 50721562201.

It is an arithmetic number, because the mean of its divisors is an integer number (50721562201).

Almost surely, 2^101443124401 is an apocalyptic number.

It is an amenable number.

101443124401 is a deficient number, since it is larger than the sum of its proper divisors (1).

101443124401 is an equidigital number, since it uses as much as digits as its factorization.

101443124401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 101443124401 its reverse (104421344101), we get a palindrome (205864468502).

The spelling of 101443124401 in words is "one hundred one billion, four hundred forty-three million, one hundred twenty-four thousand, four hundred one".