10145314631 has 2 divisors, whose sum is σ = 10145314632. Its totient is φ = 10145314630.

The previous prime is 10145314591. The next prime is 10145314633. The reversal of 10145314631 is 13641354101.

It is a strong prime.

It is an emirp because it is prime and its reverse (13641354101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10145314631 is a prime.

It is a super-2 number, since 2×10145314631² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 10145314633, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10145314594 and 10145314603.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10145314633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5072657315 + 5072657316.

It is an arithmetic number, because the mean of its divisors is an integer number (5072657316).

Almost surely, 2^10145314631 is an apocalyptic number.

10145314631 is a deficient number, since it is larger than the sum of its proper divisors (1).

10145314631 is an equidigital number, since it uses as much as digits as its factorization.

10145314631 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 10145314631 its reverse (13641354101), we get a palindrome (23786668732).

The spelling of 10145314631 in words is "ten billion, one hundred forty-five million, three hundred fourteen thousand, six hundred thirty-one".