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10147256893 is a prime number
BaseRepresentation
bin10010111001101001…
…01101101000111101
3222012011212001121101
421130310231220331
5131240144210033
64354522533101
7506313155224
oct113464555075
928164761541
1010147256893
114337953324
121b72367191
13c59368927
146c3935cbb
153e5c9997d
hex25cd2da3d

10147256893 has 2 divisors, whose sum is σ = 10147256894. Its totient is φ = 10147256892.

The previous prime is 10147256891. The next prime is 10147256923. The reversal of 10147256893 is 39865274101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10103868324 + 43388569 = 100518^2 + 6587^2 .

It is a cyclic number.

It is not a de Polignac number, because 10147256893 - 21 = 10147256891 is a prime.

Together with 10147256891, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10147256891) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5073628446 + 5073628447.

It is an arithmetic number, because the mean of its divisors is an integer number (5073628447).

It is a 2-persistent number, because it is pandigital, and so is 2⋅10147256893 = 20294513786, but 3⋅10147256893 = 30441770679 is not.

Almost surely, 210147256893 is an apocalyptic number.

It is an amenable number.

10147256893 is a deficient number, since it is larger than the sum of its proper divisors (1).

10147256893 is an equidigital number, since it uses as much as digits as its factorization.

10147256893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 362880, while the sum is 46.

The spelling of 10147256893 in words is "ten billion, one hundred forty-seven million, two hundred fifty-six thousand, eight hundred ninety-three".