Base | Representation |
---|---|
bin | 10010111010011110… |
… | …10101000100001101 |
3 | 222012122222112120101 |
4 | 21131033111010031 |
5 | 131243440443000 |
6 | 4355332251101 |
7 | 506426365060 |
oct | 113517250415 |
9 | 28178875511 |
10 | 10154234125 |
11 | 4340889432 |
12 | 1b74770a91 |
13 | c5a93c679 |
14 | 6c48308d7 |
15 | 3e66c6e6a |
hex | 25d3d510d |
10154234125 has 32 divisors (see below), whose sum is σ = 15245118720. Its totient is φ = 6596424000.
The previous prime is 10154234059. The next prime is 10154234137. The reversal of 10154234125 is 52143245101.
10154234125 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10154234125 - 213 = 10154225933 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10154234093 and 10154234102.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 288766 + ... + 322015.
It is an arithmetic number, because the mean of its divisors is an integer number (476409960).
Almost surely, 210154234125 is an apocalyptic number.
It is an amenable number.
10154234125 is a deficient number, since it is larger than the sum of its proper divisors (5090884595).
10154234125 is an equidigital number, since it uses as much as digits as its factorization.
10154234125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 610822 (or 610812 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 10154234125 its reverse (52143245101), we get a palindrome (62297479226).
The spelling of 10154234125 in words is "ten billion, one hundred fifty-four million, two hundred thirty-four thousand, one hundred twenty-five".
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