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101553345342263 is a prime number
BaseRepresentation
bin10111000101110010111011…
…000100110010101100110111
3111022120101221020121211111102
4113011302323010302230313
5101302322222401423023
6555552543544200315
730250662365534063
oct2705627304625467
9438511836554442
10101553345342263
112a3a3593a56791
12b481875a6909b
1344885933c8919
141b112cb1ccaa3
15bb198006b628
hex5c5cbb132b37

101553345342263 has 2 divisors, whose sum is σ = 101553345342264. Its totient is φ = 101553345342262.

The previous prime is 101553345342259. The next prime is 101553345342271. The reversal of 101553345342263 is 362243543355101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 101553345342263 - 22 = 101553345342259 is a prime.

It is a super-2 number, since 2×1015533453422632 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101553345342233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50776672671131 + 50776672671132.

It is an arithmetic number, because the mean of its divisors is an integer number (50776672671132).

Almost surely, 2101553345342263 is an apocalyptic number.

101553345342263 is a deficient number, since it is larger than the sum of its proper divisors (1).

101553345342263 is an equidigital number, since it uses as much as digits as its factorization.

101553345342263 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888000, while the sum is 47.

Adding to 101553345342263 its reverse (362243543355101), we get a palindrome (463796888697364).

The spelling of 101553345342263 in words is "one hundred one trillion, five hundred fifty-three billion, three hundred forty-five million, three hundred forty-two thousand, two hundred sixty-three".