Base | Representation |
---|---|
bin | 10111000101110010111011… |
… | …000100110010101100110111 |
3 | 111022120101221020121211111102 |
4 | 113011302323010302230313 |
5 | 101302322222401423023 |
6 | 555552543544200315 |
7 | 30250662365534063 |
oct | 2705627304625467 |
9 | 438511836554442 |
10 | 101553345342263 |
11 | 2a3a3593a56791 |
12 | b481875a6909b |
13 | 44885933c8919 |
14 | 1b112cb1ccaa3 |
15 | bb198006b628 |
hex | 5c5cbb132b37 |
101553345342263 has 2 divisors, whose sum is σ = 101553345342264. Its totient is φ = 101553345342262.
The previous prime is 101553345342259. The next prime is 101553345342271. The reversal of 101553345342263 is 362243543355101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101553345342263 - 22 = 101553345342259 is a prime.
It is a super-2 number, since 2×1015533453422632 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101553345342233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50776672671131 + 50776672671132.
It is an arithmetic number, because the mean of its divisors is an integer number (50776672671132).
Almost surely, 2101553345342263 is an apocalyptic number.
101553345342263 is a deficient number, since it is larger than the sum of its proper divisors (1).
101553345342263 is an equidigital number, since it uses as much as digits as its factorization.
101553345342263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888000, while the sum is 47.
Adding to 101553345342263 its reverse (362243543355101), we get a palindrome (463796888697364).
The spelling of 101553345342263 in words is "one hundred one trillion, five hundred fifty-three billion, three hundred forty-five million, three hundred forty-two thousand, two hundred sixty-three".
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