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101556400121941 is a prime number
BaseRepresentation
bin10111000101110101110001…
…001001110110100001010101
3111022120200211010201201102111
4113011311301021312201111
5101302400001412400231
6555554211030511021
730251131160662222
oct2705656111664125
9438520733651374
10101556400121941
112a3a4911331996
12b482388b05471
13448895c24cc6b
141b114dabb4949
15bb1aad3314b1
hex5c5d71276855

101556400121941 has 2 divisors, whose sum is σ = 101556400121942. Its totient is φ = 101556400121940.

The previous prime is 101556400121899. The next prime is 101556400122091. The reversal of 101556400121941 is 149121004655101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 64136937170916 + 37419462951025 = 8008554^2 + 6117145^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101556400121941 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101556400121894 and 101556400121903.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101556500121941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50778200060970 + 50778200060971.

It is an arithmetic number, because the mean of its divisors is an integer number (50778200060971).

Almost surely, 2101556400121941 is an apocalyptic number.

It is an amenable number.

101556400121941 is a deficient number, since it is larger than the sum of its proper divisors (1).

101556400121941 is an equidigital number, since it uses as much as digits as its factorization.

101556400121941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 40.

The spelling of 101556400121941 in words is "one hundred one trillion, five hundred fifty-six billion, four hundred million, one hundred twenty-one thousand, nine hundred forty-one".