101642117 has 2 divisors, whose sum is σ = 101642118. Its totient is φ = 101642116.

The previous prime is 101642113. The next prime is 101642141. The reversal of 101642117 is 711246101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98922916 + 2719201 = 9946^2 + 1649^2 .

It is a cyclic number.

It is not a de Polignac number, because 101642117 - 2² = 101642113 is a prime.

It is a super-2 number, since 2×101642117² = 20662239896483378, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101642092 and 101642101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101642113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50821058 + 50821059.

It is an arithmetic number, because the mean of its divisors is an integer number (50821059).

Almost surely, 2^101642117 is an apocalyptic number.

It is an amenable number.

101642117 is a deficient number, since it is larger than the sum of its proper divisors (1).

101642117 is an equidigital number, since it uses as much as digits as its factorization.

101642117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336, while the sum is 23.

The square root of 101642117 is about 10081.7715209183. The cubic root of 101642117 is about 466.6857792059.

Adding to 101642117 its reverse (711246101), we get a palindrome (812888218).

The spelling of 101642117 in words is "one hundred one million, six hundred forty-two thousand, one hundred seventeen".