Base | Representation |
---|---|
bin | 11101100101100000110… |
… | …10011011100110001010 |
3 | 10121011221122120021122220 |
4 | 32302300122123212022 |
5 | 113123414413010100 |
6 | 2055001241554510 |
7 | 133305413301513 |
oct | 16626032334612 |
9 | 3534848507586 |
10 | 1016572000650 |
11 | 3621424352a8 |
12 | 145027aa5a36 |
13 | 74b296c619b |
14 | 372b9353a0a |
15 | 1b69b598aa0 |
hex | ecb069b98a |
1016572000650 has 48 divisors (see below), whose sum is σ = 2522673859968. Its totient is φ = 270916480000.
The previous prime is 1016572000637. The next prime is 1016572000667. The reversal of 1016572000650 is 560002756101.
1016572000650 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×10165720006503 (a number of 37 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1876386 + ... + 2356685.
It is an arithmetic number, because the mean of its divisors is an integer number (52555705416).
Almost surely, 21016572000650 is an apocalyptic number.
1016572000650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1016572000650 is an abundant number, since it is smaller than the sum of its proper divisors (1506101859318).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1016572000650 is a wasteful number, since it uses less digits than its factorization.
1016572000650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4234687 (or 4234682 counting only the distinct ones).
The product of its (nonzero) digits is 12600, while the sum is 33.
Adding to 1016572000650 its reverse (560002756101), we get a palindrome (1576574756751).
The spelling of 1016572000650 in words is "one trillion, sixteen billion, five hundred seventy-two million, six hundred fifty", and thus it is an aban number.
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