Base | Representation |
---|---|
bin | 10010111100001110… |
… | …11101001100100111 |
3 | 222020200200001112000 |
4 | 21132013131030213 |
5 | 131311222304440 |
6 | 4401015500343 |
7 | 506665425150 |
oct | 113607351447 |
9 | 28220601460 |
10 | 10168947495 |
11 | 4349118843 |
12 | 1b796876b3 |
13 | c609c16c5 |
14 | 6c6780927 |
15 | 3e7b31730 |
hex | 25e1dd327 |
10168947495 has 64 divisors (see below), whose sum is σ = 21100400640. Its totient is φ = 4549734144.
The previous prime is 10168947487. The next prime is 10168947499. The reversal of 10168947495 is 59474986101.
10168947495 is a `hidden beast` number, since 1 + 0 + 1 + 6 + 89 + 474 + 95 = 666.
It is not a de Polignac number, because 10168947495 - 23 = 10168947487 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10168947499) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 70062 + ... + 158891.
It is an arithmetic number, because the mean of its divisors is an integer number (329693760).
Almost surely, 210168947495 is an apocalyptic number.
10168947495 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
10168947495 is an abundant number, since it is smaller than the sum of its proper divisors (10931453145).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10168947495 is a wasteful number, since it uses less digits than its factorization.
10168947495 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 229021 (or 229015 counting only the distinct ones).
The product of its (nonzero) digits is 2177280, while the sum is 54.
The spelling of 10168947495 in words is "ten billion, one hundred sixty-eight million, nine hundred forty-seven thousand, four hundred ninety-five".
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