Base | Representation |
---|---|
bin | 11101101000110111110… |
… | …11100101000001100101 |
3 | 10121100121100211102201002 |
4 | 32310123323211001211 |
5 | 113141113204232013 |
6 | 2055500240443045 |
7 | 133401205626653 |
oct | 16643373450145 |
9 | 3540540742632 |
10 | 1018375852133 |
11 | 36298868a652 |
12 | 145450019485 |
13 | 75056334323 |
14 | 3740ab4ddd3 |
15 | 1b754b13358 |
hex | ed1bee5065 |
1018375852133 has 2 divisors, whose sum is σ = 1018375852134. Its totient is φ = 1018375852132.
The previous prime is 1018375852037. The next prime is 1018375852139. The reversal of 1018375852133 is 3312585738101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1012291540129 + 6084312004 = 1006127^2 + 78002^2 .
It is a cyclic number.
It is not a de Polignac number, because 1018375852133 - 222 = 1018371657829 is a prime.
It is a super-2 number, since 2×10183758521332 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1018375852139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 509187926066 + 509187926067.
It is an arithmetic number, because the mean of its divisors is an integer number (509187926067).
Almost surely, 21018375852133 is an apocalyptic number.
It is an amenable number.
1018375852133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1018375852133 is an equidigital number, since it uses as much as digits as its factorization.
1018375852133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 604800, while the sum is 47.
The spelling of 1018375852133 in words is "one trillion, eighteen billion, three hundred seventy-five million, eight hundred fifty-two thousand, one hundred thirty-three".
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