Base | Representation |
---|---|
bin | 10111001100010010111001… |
… | …111100100010101101110111 |
3 | 111101011002211120210212010121 |
4 | 113030102321330202231313 |
5 | 101332132001232014312 |
6 | 1000534053212032411 |
7 | 30325154106150223 |
oct | 2714227174425567 |
9 | 441132746725117 |
10 | 102000003001207 |
11 | 2a555a5a6178a3 |
12 | b53434a762707 |
13 | 44bb7361bb37c |
14 | 1b28b7dc43783 |
15 | bbd3c2b91707 |
hex | 5cc4b9f22b77 |
102000003001207 has 2 divisors, whose sum is σ = 102000003001208. Its totient is φ = 102000003001206.
The previous prime is 102000003001181. The next prime is 102000003001271. The reversal of 102000003001207 is 702100300000201.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 102000003001207 - 223 = 101999994612599 is a prime.
It is a super-2 number, since 2×1020000030012072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102000003001907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51000001500603 + 51000001500604.
It is an arithmetic number, because the mean of its divisors is an integer number (51000001500604).
Almost surely, 2102000003001207 is an apocalyptic number.
102000003001207 is a deficient number, since it is larger than the sum of its proper divisors (1).
102000003001207 is an equidigital number, since it uses as much as digits as its factorization.
102000003001207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 16.
Adding to 102000003001207 its reverse (702100300000201), we get a palindrome (804100303001408).
The spelling of 102000003001207 in words is "one hundred two trillion, three million, one thousand, two hundred seven".
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